Acceleration of an electron at a moment in a magentic field vec B, = ,2hat{i} + 3hat{j} + 4hat

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4.Moving Charges and Magnetism

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The acceleration of an electron at a moment in a magentic field $\vec B\, = \,2\hat i + 3\hat j + 4\hat k$ is $\vec a\, = \,x\hat i - 2\hat j + \hat k$. The value of $x$ is

A

$0.5$

B

$1$

C

$2.5$

D

$1.5$

Solution

$ \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{a}} =0 $

$ 2 \mathrm{x}-6+4 =0 $

$ 2 \mathrm{x}=2 $

$x=1$

Standard 12

Physics

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